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A projectile is thrown with a speed of 98 ms^(-1) in a direction 30^(@)abovethe horizontal . Find the time of flight , range and height to which it rises . |
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Answer» SOLUTION :Given : Initial velocity` = u = 98 ms^(-1)` Time of flight ` = t(2 u sin theta)/(g) = ( 2 xx 98 sin 30^(@))/(9 . 8)` `= (2 xx 98) / ( 9 . 8) xx (1)/(2) = 10 secs` Range R ` = v_(x) xx t = u cos theta xx t` ` = 98 xx cos 30^(@) xx 10 = 848 . 7 m ` Maximum height , `h_("max") = (u^(2) sin^(2) theta)/(2g)` ` =((98)^(2) xx (sin 30)^(2))/( 2 xx 9 . 8) = 122. 5 m ` `h_("max") = 122.5m ` |
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