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A projectile is thrown with a velocity `u_(0)` at an angle `theta` with the horizontal. The ratio of the rate of change of speed w.r.t. time, at highest point to that at the point of projection, isA. `g sin theta`B. `- g sin theta`C. zeroD. g |
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Answer» Correct Answer - C `(dv)/(dt)` (at the top ) = 0 as tangential acceleration at the top = 0 `(dv)/(dt)` (at the starting point) `= g sin theta` So, required ratio = zero |
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