1.

A projectile is thrown with speed v0 at an angle θ above horizontal from top of a tower of height h. The speed of projectile when it makes an angle β with vertical isOptions:

Answer»
  • A body is projected with a velocity v0 at an angle θ then its horizontal velocity becomes v0 cos θ and vertical velocity becomes v0 sin θ
  • At certain point, it is given that the velocity makes angle β with vertical   

                 let the velocity at that point be 'v' then the horizontal velocity becomes vsinβ

                            vertical velocity becomes vcosβ

            In a projectile, horizontal velocity is always constant as the acceleration in that direction is 0

                so,    v0 cos θ = vsinβ 

                              v = v0 cos θ/sinβ 


Discussion

No Comment Found

Related InterviewSolutions