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A projectile thrown with a speed v at an angle `theta` has a range R on the surface of earth. For same v and `theta`, its range on the surface of moon will beA. 36RB. `(R)/(36)`C. `(R)/(16)`D. 6R |
Answer» Correct Answer - D `R prop (1)/(g) :. R_("moon") = 6R_("earth")` |
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