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A proton accelerated by a potential difference `500 KV` moves though a transverse field of `0.51 T` as shown in figure. The angle `theta` through which the proton deviates from the intial direction of its motion is A. `15^(@)`B. `30^(@)`C. `45^(@)`D. `60^(@)` |
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Answer» Correct Answer - B |
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