A proton accelerated by a potential difference V=500 kV moves through a transverse magnetic field B=0.51 T as shown in figure. Then the angle θ through which the proton deviates from the initial direction of its motion is (approximately)

A proton accelerated by a potential difference V=500 kV moves through

1.	A proton accelerated by a potential difference V=500 kV moves through a transverse magnetic field B=0.51 T as shown in figure. Then the angle θ through which the proton deviates from the initial direction of its motion is (approximately)
Answer» A proton accelerated by a potential difference $V = 500 kV$ moves through a transverse magnetic field $B = 0.51 T$ as shown in figure. Then the angle $θ$ through which the proton deviates from the initial direction of its motion is (approximately)

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A proton accelerated by a potential difference V=500 kV moves through a transverse magnetic field B=0.51 T as shown in figure. Then the angle θ through which the proton deviates from the initial direction of its motion is (approximately)

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