A proton and a deuteron both having the same kinetic energy, enter perpendicularly into a uniform magnetic field `B`. For motion of proton and deuteron on circular path or radius `R_(p)` and `R_(d)` respectively, the correct statement isA. `R_(d)=sqrt2R_(p)`B. `R_(d)=R_(p)//sqrt2`C. `R_(d)=R_(p)`D. `R_(d)=2R_(p)`

A proton and a deuteron both having the same kinetic energy, enter per

1.	A proton and a deuteron both having the same kinetic energy, enter perpendicularly into a uniform magnetic field `B`. For motion of proton and deuteron on circular path or radius `R_(p)` and `R_(d)` respectively, the correct statement isA. `R_(d)=sqrt2R_(p)`B. `R_(d)=R_(p)//sqrt2`C. `R_(d)=R_(p)`D. `R_(d)=2R_(p)`
Answer» Correct Answer - A `(mv^(2))/(R)=qvB.` For proton `R_(p)=(mv)/(qB)=sqrt(2m_(p)E)/(qB)` and for deuteron `R_(d)=(sqrt(2m_(d)E))/(qB)` `implies (R_(d))/(R_(p))=sqrt(m_(d)/(m_(p)))=sqrt(2) impliesR_(d)=sqrt(2)R_(p)`

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