A proton and a deutron are acclerated through the same accelerating potential. Which one of the two has (a) Greater value of de-Broglie wavelength associated with it, and (b) Less momentum ? Given reason to justify your answer.

A proton and a deutron are acclerated through the same accelerating po

1.	A proton and a deutron are acclerated through the same accelerating potential. Which one of the two has (a) Greater value of de-Broglie wavelength associated with it, and (b) Less momentum ? Given reason to justify your answer.
Answer» Solution :For an ACCELERATION potential V the de-Broglie WAVELENGTH of a charged particle of CHARGE q and mass m is given by `lamda=(h)/(sqrt((2mqV)))` and momentum of particle `p=sqrt(2mqV)`. As mass of DEUTRON is greater than that of proton i.e., `m_(D) gt m_(P)`, hence we conclude that (a) de-Broglie wavelength of proton is greater than that of deutron, and (b) momentum of proton is less than that of deutron.

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A proton and a deutron are acclerated through the same accelerating potential. Which one of the two has (a) Greater value of de-Broglie wavelength associated with it, and (b) Less momentum ? Given reason to justify your answer.

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