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A proton and an `alpha`-particle are accelerated, using the same potential difference. How are the de-Broglie wavelengths `lambda_(p) and lambda_(a)` related to each other?

Answer» As, `lambda=h/(sqrt(2mqV)) :. lambda prop 1/(sqrt(mq)) :. (lambda_(p))/(lambda_(alpha)) =(sqrt(m_(alpha)q_(alpha)))/(sqrt(m_(p)q_(p)))=(sqrt(4m_(p)xx2e))/(sqrt(m_(p)xxe))=sqrt8=2sqrt2`


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