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A proton and and `alpha `- particle are accelerated through a potential difference of `100 V`. The ratio of the wavelength with the proton to that associated to that associated with an `alpha` - particle isA. `sqrt(2):1`B. `2:(1)/(sqrt(2))`C. `2:1`D. `(1)/(2sqrt(2)):1` |
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Answer» Correct Answer - C `lambda =(h)/(p) =(h)/( sqrt(mqv))` For same potential difference `lambda alpha (1)/(sqrt(mq))=(lambda_(p))/(lambda_(r )) = sqrt( (m_(r)q_(r))/(m_(p)q_(p)))=2sqrt(2)` |
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