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InterviewSolution
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A proton initially has vec v = 4.0 hati- 2.0 hatj + 3.0 hatk and then 4.0 slater has vec v = -2.0 hati - 2.0 hatj + 5.0hatk(in meter per second) for that 4.0s what are (a) the proton's average acceleration vec a_(avg)in unit vector notation (b) the magnitude of vec a_(avg) and (c ) the angle between veca_(avg) and the positive direction of the x axis ? |
| Answer» <html><body><p></p>Solution :We use <a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a>. with <a href="https://interviewquestions.tuteehub.com/tag/vec-723433" style="font-weight:bold;" target="_blank" title="Click to know more about VEC">VEC</a> v_1` designating the initial <a href="https://interviewquestions.tuteehub.com/tag/velocity-1444512" style="font-weight:bold;" target="_blank" title="Click to know more about VELOCITY">VELOCITY</a> and `vec v_2` designating the later one.<br/>(a) The <a href="https://interviewquestions.tuteehub.com/tag/average-13416" style="font-weight:bold;" target="_blank" title="Click to know more about AVERAGE">AVERAGE</a> acceleration during the `Delta t = 4s` interval is<br/>`vec a_(avg) = ((-2.0 hati - 2.0 hatj + 5.0 hatk) m//s - (4.0hati - 22hatj + 3.0 hatk)m//s)/(4s)` <br/>` = (-1.5 m//s^2) hati + (0.5 m//s^2) hatk`<br/>(b) The magnitude of `vec a_(avg) ` is<br/>` sqrt( (-1.5 m//s^2)^2 + (0.5m//s^2)^2) = 1.6 m//s^2`<br/>( c) Its angle in the xz plane (measured from the +x axis is one of these <a href="https://interviewquestions.tuteehub.com/tag/possibilities-1160393" style="font-weight:bold;" target="_blank" title="Click to know more about POSSIBILITIES">POSSIBILITIES</a> :<br/>` tan^(-1) ( (0.5m//s^2)/(-1.5 m//s^2)) = - 18^@ or162^@`</body></html> | |