1.

A proton is accelerated to a velocity of3xx 10^(7) m s^(-1). If the velocity can be measured with a precision of +- 0.5%, calculate the uncertainty in position of proton [h = 6.6 xx 10^(-34)Js, mass of proton = 1.66 xx 10^(-27)kg]

Answer»


Solution :`DELTA v = (0.5)/(100) xx (3 xx 10^(7)) ms^(-1) = 1.5 xx 10^(5) m s^(-1)`
`Delta X = (h)/(4pi m Delta v) = (6.6 xx 10^(-34) KG m^(2) s^(-1))/(4 xx 3.14 xx 1.66 xx 10^(-27) kg xx 1.5 xx 10^(5) ms^(-1)) = 2.11 xx 10^(-13) m`


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