1.

A proton is moving with kinetic energy 5 x 1027 J. What is the velocity of the proton?

Answer»

\(\because\) mass of proton = 1.67 × 10−27kg

K. E. = 5 × 10−27

\(\because\) K.E = \(\frac{1}{2}\)mv2

\(\therefore\) v = \(\sqrt{\frac{2K.E}{m}}\)

\(\sqrt{\frac{2\times5\times10^{-27}}{1.6\times10^{-27}}m/s}\)

= 5.98 m/s



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