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A proton is moving with kinetic energy 5 x 1027 J. What is the velocity of the proton? |
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Answer» \(\because\) mass of proton = 1.67 × 10−27kg K. E. = 5 × 10−27 \(\because\) K.E = \(\frac{1}{2}\)mv2 \(\therefore\) v = \(\sqrt{\frac{2K.E}{m}}\) = \(\sqrt{\frac{2\times5\times10^{-27}}{1.6\times10^{-27}}m/s}\) = 5.98 m/s |
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