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A proton is projected with a velocity of `3xx10^(6) m//s` perpendicular to a uniform magnetic field of `0.6 T`.Find the acceleration of the proton.mass of proton`=5/3xx10^(-27) kg` |
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Answer» Correct Answer - A::B::D `f=qVB rArra=f/m=(qVB)/m=864/5xx10^(12) m//s^(2)` |
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