A proton is rotating along a circular path of radius 0.1 m under a centrifugal force of 4×10−13 N. If the mass of proton is 1.6×10−27 kg, the angular velocity of rotation is (in rad/s)

A proton is rotating along a circular path of radius 0.1 m under a cen

1.	A proton is rotating along a circular path of radius 0.1 m under a centrifugal force of 4×10−13 N. If the mass of proton is 1.6×10−27 kg, the angular velocity of rotation is (in rad/s)
Answer» A proton is rotating along a circular path of radius $0.1 m$ under a centrifugal force of $4 \times 10^{- 13} N$ . If the mass of proton is $1.6 \times 10^{- 27} kg$ , the angular velocity of rotation is (in rad/s)

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A proton is rotating along a circular path of radius 0.1 m under a centrifugal force of 4×10−13 N. If the mass of proton is 1.6×10−27 kg, the angular velocity of rotation is (in rad/s)

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