A proton is to circulate the earth along the equator with a speed of `1*0xx10^7ms^-1`. Find the minimum magnetic field which should be created at the equator for this purpose. The mass of proton `=1*7xx10^(-27)kg` and radius of earth `=6*37xx10^6m`.

A proton is to circulate the earth along the equator with a speed of `

1.	A proton is to circulate the earth along the equator with a speed of `10xx10^7ms^-1`. Find the minimum magnetic field which should be created at the equator for this purpose. The mass of proton `=17xx10^(-27)kg` and radius of earth `=6*37xx10^6m`.
Answer» Correct Answer - `167xx10^-8T` `qv B=mv^2//r` or `B=(mv)/(qr)=(17xx10^(-27)xx(10xx10^7))/((16xx10^(-19))xx(637xx10^6))` `=167xx10^-8T`

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A proton is to circulate the earth along the equator with a speed of `1*0xx10^7ms^-1`. Find the minimum magnetic field which should be created at the equator for this purpose. The mass of proton `=1*7xx10^(-27)kg` and radius of earth `=6*37xx10^6m`.

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A proton is to circulate the earth along the equator with a speed of `10xx10^7ms^-1`. Find the minimum magnetic field which should be created at the equator for this purpose. The mass of proton `=17xx10^(-27)kg` and radius of earth `=6*37xx10^6m`.