A proton moves at a speed of v=2×106 m/s in a region of constant magnetic field of magnitude 0.05 T. The direction of the proton with the field is θ=30∘ when it enters. When you look along the direction of the magnetic field, the path is a circle projected on a plane perpendicular to the magnetic field. How far will the proton moves along the direction of B, when two projected circles have bean completed ?

A proton moves at a speed of v=2×106 m/s in a region of constant magn

1.	A proton moves at a speed of v=2×106 m/s in a region of constant magnetic field of magnitude 0.05 T. The direction of the proton with the field is θ=30∘ when it enters. When you look along the direction of the magnetic field, the path is a circle projected on a plane perpendicular to the magnetic field. How far will the proton moves along the direction of B, when two projected circles have bean completed ?
Answer» A proton moves at a speed of $v = 2 \times 10^{6} m/s$ in a region of constant magnetic field of magnitude $0.05 T$ . The direction of the proton with the field is $θ = 30^{\circ}$ when it enters. When you look along the direction of the magnetic field, the path is a circle projected on a plane perpendicular to the magnetic field. How far will the proton moves along the direction of $B$ , when two projected circles have bean completed ?

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