A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. The direction of the proton when it enters this field is `theta = 30^(@)` to the field. When you look along the direction of the magnetic field, then the path is a circle projected on a plane perpendicular to the magnetic field. How far will the proton move along the direction of B when two projected circles have been completed?A. `4.35 m`B. `0.209 m`C. `2.82 m`D. `2.41 m`

A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant

1.	A proton moves at a speed `v = 2xx10^(6) m//s` in a region of constant magnetic field of magnitude B = 0.05 T. The direction of the proton when it enters this field is `theta = 30^(@)` to the field. When you look along the direction of the magnetic field, then the path is a circle projected on a plane perpendicular to the magnetic field. How far will the proton move along the direction of B when two projected circles have been completed?A. `4.35 m`B. `0.209 m`C. `2.82 m`D. `2.41 m`
Answer» Correct Answer - A

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