A proton of charge 1.6 x 10-1°C and mass 1.67 x 10-27 kg is accelerat

1.	A proton of charge 1.6 x 10-1°C and mass 1.67 x 10-27 kg is accelerated by a potential difference of 6 x 105 volts. Then its enters perpendicularly into a magnetic field of intensity 0.5 Tesla. Find the radius of the circular path of the proton.
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A proton of charge 1.6 x 10-1°C and mass 1.67 x 10-27 kg is accelerated by a potential difference of 6 x 105 volts. Then its enters perpendicularly into a magnetic field of intensity 0.5 Tesla. Find the radius of the circular path of the proton.

Answer»

Answer:

you will GET your answer at toppr.com please go and CHECK there once.

HOPE it's helpful