InterviewSolution
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A proton of mass `1.67xx10^(-27)kg` and charge `1.6xx10^(-19)c` is projected with a speed of `2xx10^(6)m//s` at an angle of `60^(@)` to the x-axis. If a uniform magnetic field of `0.104` Tesla is applied along Y-axis, the path of proton isA. a circle of radius `~=0.1m` and time perio `pi xx 10^(-7)s`B. a circle of radius `~=0.2m` and time period `2pixx10^(-7)s`C. a helix of radius `~=0.1m` and time period `2pixx10^(-7)s`D. a helix of radius `~=0.2m` and time period `4pixx10^(-7)s` |
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Answer» Correct Answer - C `v_(_|_)=v cos 60`, find `r=(mv_(_|_))/(qB),r=0.1m` Hence `t=(2pim)/(qB)=2pixx10^(-7)s`. Hence answer is `(c )` and path is helix. |
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