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A proton when accelerated through a potential difference of V volt has a wavelength `lamda` associated with it. An alpha-particle in order to have the same `lamda` must be accelerated through a potential difference ofA. V voltB. 4V voltC. 2V voltD. `V/8` volt |
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Answer» Correct Answer - D `lambda=h/(sqrt(2m_peV))`..(i) `lambda=h/(sqrt(2m_alpha(2e)V_alpha))`..(ii) equation (i) &(ii) we have `2m_peV=2xx4xxm_pxx2eV_alpha` `implies V_alpha=V/8` |
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