1.

A pulsar is a rapidly rotating neutron star, the result of the gravitational collapse of an ordinary star that has used up its fuel supply. A certain pulsar has a rotational period of `T=0.033 sec` and radius `R=1//38 km`. The tangential speed of a point on the equator is `"___________" (km//s)`

Answer» `omega=2pi//T=2pi//0.033=190rad//sec`
`v_(t)=omegar=190xx1//38=5`


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