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A pump on the ground floor of a building can pump up water tofill a tank of volume 30 m^(3) in 15 min . If the tank is 40 m above the ground , and the efficiency of the pump is 30% how much electric power is consumed by the pump? |
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Answer» <P> Solution :`P= W/t = (MGH)/t`` = (30 xx10^(3) xx9.8 xx40)/(15xx60)` ` 13.07 KW` `eta =("Output power ")/("Input power") [ " Where " m = V_(RHO) = 30 xx10^(3)kg]` ` :."Input power " =("Output power")/eta` `=(13.07)/(0.30)` ` = 43.56 kW` `APPROX 43.6 kW` |
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