1.

A pump on the ground floor of a building can pump up water tofill a tank of volume 30 m^(3) in 15 min . If the tank is 40 m above the ground , and the efficiency of the pump is 30% how much electric power is consumed by the pump?

Answer»

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Solution :`P= W/t = (MGH)/t`
` = (30 xx10^(3) xx9.8 xx40)/(15xx60)`
` 13.07 KW`
`eta =("Output power ")/("Input power") [ " Where " m = V_(RHO) = 30 xx10^(3)kg]`
` :."Input power " =("Output power")/eta`
`=(13.07)/(0.30)`
` = 43.56 kW`
`APPROX 43.6 kW`


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