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A pure gas that is `14.3%` hydrogen and `85.7%` carbon by mass has a density of `2.5g L^(-1)` at `0^(@)C` and 1 atm pressure. What is the molecular formula of the gas :A. `CH_(2)`B. `C_(2)H_(4)`C. `C_(4)H_(8)`D. `C_(6)H_(12)` |
Answer» Correct Answer - C `% "mol Simples ratio"` `C" " 85.7 " "85.7//12 = 7.14" "7.14// 7.14 = 1 " "1` `H " "14.3" " 14.3//1 = 14.3" " 14.3//7.14 = 2 " "2` `:.` Emperical formal `=CH_(2)` `:. PMw = DRT` `Mw = (DRT)/(P) = (2.5 xx 0821 xx 273)/(1) =56` `n = ("molecular wt")/("Ewt") = (56)/(14) = 4` Molecular formula `= n xx E.F` `= 4 xx CH_(2)` `= C_(4) H_(8)` . |
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