A pure semiconductor has equal electron and hole concentration of `10^(6)m^(-3)`. Dopping by indium increases `n_(h)` to `4.5xx10^(22)m^(0k3)`. What is `n_(e)` in the dopped semiconductor?A. `10^(6)m^(-3)`B. `10^(22)m^(-3)`C. `(10^(32))/(4.5xx10^(22))m^(-3)`D. `4.5xx10^(22)m^(-3)`

A pure semiconductor has equal electron and hole concentration of `10^

1.	A pure semiconductor has equal electron and hole concentration of `10^(6)m^(-3)`. Dopping by indium increases `n_(h)` to `4.5xx10^(22)m^(0k3)`. What is `n_(e)` in the dopped semiconductor?A. `10^(6)m^(-3)`B. `10^(22)m^(-3)`C. `(10^(32))/(4.5xx10^(22))m^(-3)`D. `4.5xx10^(22)m^(-3)`
Answer» Correct Answer - A `n_(e)h_(e)=n^(2)` or `h_(e)=(n^(2))/(n_(h))=(10^(16)xx10^(16))/(4.5xx10^(22))` `=(10^(32))/(4.5xx10^(22))m^(-3)`

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A pure semiconductor has equal electron and hole concentration of `10^(6)m^(-3)`. Dopping by indium increases `n_(h)` to `4.5xx10^(22)m^(0k3)`. What is `n_(e)` in the dopped semiconductor?A. `10^(6)m^(-3)`B. `10^(22)m^(-3)`C. `(10^(32))/(4.5xx10^(22))m^(-3)`D. `4.5xx10^(22)m^(-3)`

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