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A purified pepsin was subjected to amino acid analysis. The amino acid present in smallest amount was lysine, `C_(6)H_(14)N_(2)O_(2)` and the amount of lysine was found to be 0.43 g per 100 g of protein. The minimum molecular mass of protein isA. 34000B. 14600C. 43000D. None to these.

Answer» Correct Answer - A
Mol. Mass of lysine `(C_6H_(14)N_2O_2)`=146
Min.mol. Mass `=(100 xx "Mol . Mass of lysine")/("% of lysine in the pepsin")`
`(100xx146)/(0.43)=(1460000)/(43)`= 340000 (approx)


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