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A quantity of hydrogen gas occupies a volume of `30.0 mL` at a certain temperature and pressure. What volume would half of this mass of hydrogen occupy at triple the initial temperature, if the pressure was one-ninth that of the original gas?A. `270 mL`B. `90 mL`C. `405 mL`D. `137 mL` |
Answer» `P_(1)V_(1n_(1)RT_(1)` `P_(2)V_(2)=n_(2)RT_(2)` `(P_(2)V_(2))/(P_(1)V_(1))=(n_(2)T_(2))/(n_(1)T_(1))` `(P_(1))/(9P_(1))(V_(2))/(30)=(1)/(2)(n_(1))/(n_(1))(3T_(1))/(T_(1))` `V_(2)=405 mL` |
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