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A quantity of hydrogen gas occupies a volume of `30.0 mL` at a certain temperature and pressure. What volume would half of this mass of hydrogen occupy at triple the initial temperature, if the pressure was one-ninth that of the original gas? |
Answer» `{:(,"Initial","Final"),(V, 30mL,V_(2)),(P,P_(1), P_(2)=P_(2)=1//9P_(1)),(T,T_(1),T_(2)=3T_(1)),(n,n_(1),n_(2)=1//2n_(1)):}` Using gas equation, `PV=nRT`, we get `(P_(1)V_(1))/(P_(2)V_(2))=(n_(1)RT_(1))/(n_(2)RT_(2))` `(P_(1)xx30)/((1)/(9)P_(1)xxV_(2))=(nT_(1))/(((1)/(2)n_(1))(3T_(1)))` `V_(2)=(1)/(2)xx3xx9xx30.0=405 mL` |
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