A quillof 0.100 gm is falling with a velocity of (-0.05hatj)m//s. When blown from lower side, its velocity changes to (0.2hati+0.15hatj)m//s. The change in its momentum will be……..kg m/s.

A quillof 0.100 gm is falling with a velocity of (-0.05hatj)m//s. When

1.	A quillof 0.100 gm is falling with a velocity of (-0.05hatj)m//s. When blown from lower side, its velocity changes to (0.2hati+0.15hatj)m//s. The change in its momentum will be……..kg m/s.
Answer» `2xx10^(-2)hati+2xx10^(-2)hatj` `2xx10^(-2)hati-2xx10^(-2)hatj` `2xx10^(-2)hati+1xx10^(-2)hatj` `2xx10^(-5)hati+2xx10^(-5)hatj` SOLUTION :`Deltavecp=VEC(p_(2))-vec(p_(1))=mvecv_(2)-mvecv_(1)` `=m[vec(v_(2))-vec(v_(1))]` `=0.1xx10^(-3)[0.2hati+0.15hatj-(-0.05)hatj]` `=10^(-4)[0.2hati+0.20hatj]` `=[2xx10^(-5)hati+2xx10^(-5)hatj]kgm//s`