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A racing car has a uniform acceleration of `4 m//s^(2)`. What distance will it cover in `10 s` after start ? |
Answer» Here, `" "` Distance covered, s = ? `" "` (To be caculated) `" "` Initial velocity, `u` = 0 `" "` Acceleration, `a= 4" m" s^(-2)` And, `" "` Time, `t=10` s Now, `" "s=ut+(1)/(2) at^(2)` So, `" " s= 0xx10+ (1)/(2) xx 4 xx (10)^(2)` `" "s = 0+2xx100` `" "s=200" m"` Thus, the distance covered by the racing car in 10 s is 200 metres. |
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