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A racing car travelling at 35 ms^(-1) along a circular path of radius 700 m, starts picking up speed at the rate of 2 ms^(-2) What is its total acceleration ? |
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Answer» Solution :`v = 35 ms^(-1),r = 700 m`, TANGENTIAL accleration `=a_(1) = 2 ms^(-2)` RADIAL acceleration `=a_(r) = v^(2)/r = (35 xx 35)/700 = 1.75 ms^(-2)` Total acceleration `a = sqrt(a_(l)^(2) + a_(r)^(2)) = sqrt(2^(2) + (1.75)^(2)) = 2.66 ms^(-2)` |
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