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    				| 1. | A radioactive element has rate of disintegration `10,000` disintegrations per minute at a particular instant. After four minutes it becomes `2500` disintegrations per minute. The decay constant per minute isA. `0.2 log_(e) 2`B. `0.5 log_(e) 2`C. `0.6 log_(e) 2`D. `0.8 log_(e) 2` | 
| Answer» Correct Answer - B Given `N_(0) = 10,000` disintegeration/min `N = 2500` disintegeration/min `t = 4` min From the radioactive decay law, we have `(N)/(N_(0)) = e^(-lambdat)` `:. (2500)/(10000) = e^(-lambdatxx 4)` `rArr 1/4 = e^(-4lambda) rArr e^(4lambda) = 4` `rArr 4 lambda = log_(e) 4 rArr 4 lambda = log_(e) 2^(2)` `rArr 4 lambda = 2 log_(e) 2` `lambda = 2/4 log_(e) 2` `:. lambda = 0.5 log_(e) 2` | |