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A radioactive nucleus (initial mass number A and atomic number Z) emits 2α and 2 positrons. The ratio of number of neutrons to that of proton in the final nucleus will be(a) \(\frac{A-Z-4}{Z-2}\)(b) \(\frac{A-Z-2}{Z-6}\)(c) \(\frac{A-Z-4}{Z-6}\)(d) \(\frac{A-Z-12}{Z-4}\) |
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Answer» (b) \(\frac{A-Z-2}{Z-6}\) |
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