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A radioactive nuclide is produced at a constant rate of `alpha` per second . It’s decay constant is `lambda`. If `N_(0)` be the no. of nuclei at time t=0 , then max. no. nuclei possible are :A. `(alpha)/(lambda)`B. `N_(0) + (alpha)/(lambda)`C. `N_(0)`D. `(lambda)/(alpha) + N_(0)` |
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Answer» Maximum number of nuclei will be present when Rate of decay = rate of formation `lambda N = alpha` `N = (alpha)/(lambda)` |
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