1.

A radioactive substance disintegrates 1/64 of initial value in 60 s. The half-life of this substance isA. 5 sB. 10 sC. 30 sD. 20 s

Answer» Correct Answer - B
We have , `1/64=((1)/(2))^(n)n=6`
6 half-lives are equal to 60 s.
`therefore` 1 half-life = 10 s


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