1.

A radioactive substance with decay constant of 0.5s^(-1) is being produced at a constant rate of 50 nuclei per second . If there are no nuclei present initially, the time (in second) after which 25 nuclei will be present is :

Answer»

1
LN 2
ln(4/3)
2 ln (4/3)

Solution :`(dN)/(dt)=50-(N)/(0.5)`
`underset(0)OVERSET(N)int (dN)/(50-2N)=underset(0)overset(t)int dt`
`RARR N= (100(1-e^(-t//2)))`
N=25
`rArr t=2ln ((4)/(3))`


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