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A randdom variable X takes the values 1, 2, 3 and 4 such that 2P(X=1)=3P (X=2)=P(X=3)=5P(X=4). If sigma^(2) is the variance and mu is the mean of X. Then, sigma^(2)+mu^(2)= |
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Answer» `(421)/(61)` |
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