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A random variable X can take only two values, 2 and 4 i.e., P(2) = 0.45 and P(4) = 0.97. What is the Expected value of X?(a) 3.8(b) 2.9(c) 4.78(d) 5.32The question was posed to me during an internship interview.I would like to ask this question from Discrete Probability topic in chapter Discrete Probability of Discrete Mathematics

Answer»

The CORRECT choice is (C) 4.78

For EXPLANATION: We know that E(X) = ∑ x*P(x) = 2 × 0.45 + 4 × 0.97 = 4.78, where x={2,4}.



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