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A random variable X has the following probability distribution Determine P(X |
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Answer» <P> SOLUTION :`P(Xlt3)`=P(X=0 or 1 or 2)=P(X=0)+P(X=1)+P(X=2) =P(0)+P(1)+P(2) (`because` X=0, X=1 and X=2 are THREE mutually EXCLUSIVE CASES) =0+k+2k=3k=3/13 |
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