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A random variable X has the following probability distribution:(a) Find k(b) Find P(0 < X < 4)(c) Obtain cumulative distribution function (c.d.f) of X. |
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Answer» (a) K + 3K + 5K + 7K + 9K + 11K + 13K = 1 ∴ 49K = 1 ∴ K = 491 (b) P(0 < x < 4) = P(1) + P(2) + P(3) 493 + 4910 + 4921 = 4934 (c) C.D.F = (2x + 1)K, 0 ≤ x |
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