A rarr B, Graph between long_(10) P and (1)/(T) is a straight line of slope (1)/(4.606). Hence, Delta H is

A rarr B, Graph between long_(10) P and (1)/(T) is a straight line of

1.	A rarr B, Graph between long_(10) P and (1)/(T) is a straight line of slope (1)/(4.606). Hence, Delta H is
Answer» <html><body><p>1 cal<br/>`-4.18` J<br/>4 cal<br/>`-1` cal</p>Solution :`Delta G^(0) = - <a href="https://interviewquestions.tuteehub.com/tag/rt-615359" style="font-weight:bold;" target="_blank" title="Click to know more about RT">RT</a> ln K_(P) = - RT ln P= - 2.303RT log P` <br/> log P `= (-Delta G^(0))/(2.303R).(1)/(T) = (-Delta <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>^(0))/(2.303RT) + (Delta S^(0))/(2.303R)` <br/> `<a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a>` <a href="https://interviewquestions.tuteehub.com/tag/slope-15649" style="font-weight:bold;" target="_blank" title="Click to know more about SLOPE">SLOPE</a> `= (-Delta H^(0))/(2.303RT) = (1)/(4.606)` <br/> `rArr Delta H^(0) = - 1 "cal" = -4.18J`</body></html>