A rarr B, Graph between long_(10) P and (1)/(T) is a straight line of slope (1)/(4.606). Hence, Delta H is

A rarr B, Graph between long_(10) P and (1)/(T) is a straight line of

1.	A rarr B, Graph between long_(10) P and (1)/(T) is a straight line of slope (1)/(4.606). Hence, Delta H is
Answer» 1 cal `-4.18` J 4 cal `-1` cal Solution :`Delta G^(0) = - RT ln K_(P) = - RT ln P= - 2.303RT log P` log P `= (-Delta G^(0))/(2.303R).(1)/(T) = (-Delta H^(0))/(2.303RT) + (Delta S^(0))/(2.303R)` `RARR` SLOPE `= (-Delta H^(0))/(2.303RT) = (1)/(4.606)` `rArr Delta H^(0) = - 1 "cal" = -4.18J`