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A ray of light coming along the line (x - 1)/(1) = (y - 2)/(2) = (z - 3)/(3), strikes the plane mirror kept along the plane through points (2, 1, 1), (3, 0, 2) and(2 , -1, -2) . Then the equation of reflected ray is: |
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Answer» `(x - 3)/(1) = (y - 3)/(5) = (z - 2)/(-5)` `2x+y-z-4=0` POINT on the line `(x-1)/(1)=(y-2)/(2)=(z-3)/(3)=R` Point on the line `(x-1)/(1)=(y-2)/(2)=(z-3)/(3)=r` is (1, 2, 3) Reflection of `(1, 2, 3)` in the plane `(x_(1)-1)/(2)=(y_(1)-2)/(1)=(z_(1)-3)/(-1)=(-2(2+2-3-4))/((2)^(2)+(1)^(2)+(-1)^(2))` `(x_(1)-1)/(2)=(y_(1)-2)/(1)=(z_(1)-3)/(-1)=(6)/(6)` `x_(1)=3` `y_(1)=3"(3, 3, 2)"` `z_(1)=2` Point of INTERSECTION of line and plane `2(1+r)+1(2+2r)-(3+3r)-4=0` `r=3` Point of intersection (4, 8, 12) Equation of line of reflection `(x-3)/(4-3)=(y-3)/(8-3)=(z-2)/(12-2),(-3)/(1)=(y-3)/(5)=(z-2)/(10)` |
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