InterviewSolution
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InterviewSolution
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A ray of light is incident at an angle of `60^@` on one face of a rectangular glass slab of thickness `0.1 m`, and refractive glass slab of thickness `0.1 m`, and refractive index `1.5`. Calculate the lateral shift produced. |
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Answer» Correct Answer - 0.0513 m Here, `i_1 = 60^@, t = 0.1 m, mu = 1.5` As `(sin i_1)/(sin r_1) = mu` :. `sin r_1 = (sin i_1)/(mu) = (sin 60^@)/(1.5) = 0.5773` `r_1 = sin^-1 (0.5773) = 35.3^@` Lateral shift `= (t sin (i_1 - r_1))/(cos r_1)` =`(0.1 sin (60^@ - 35.3^@))/(cos 35.3^@) = (0.1 sin 24.7^@)/(cos 35.3^@)` =`(0.1 xx 0.418)/(0.816) = 0.0513 m`. |
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