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A ray of light is incident normally on one of the faces of a prism of apex angle 30^@and refractive index sqrt2. The angle of deviation of the ray is ……degree. |
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Answer» Solution :Apply Snell.s LAW of refraction at P `(sin 30^@)/(sin r)=1/sqrt2` `or sin r=sqrt2 times 1/2=1/sqrt2 = sin 45^@ or r=45^@` `therefore delta=r-30^@=45^@-30^@=15^@, therefore`DEVIATION of ray=`15^@`
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