1.

A ray of light is incident normally on one of the faces of a prism of apex angle 30^@and refractive index sqrt2. The angle of deviation of the ray is ……degree.

Answer»

Solution :Apply Snell.s LAW of refraction at P `(sin 30^@)/(sin r)=1/sqrt2`
`or sin r=sqrt2 times 1/2=1/sqrt2 = sin 45^@ or r=45^@`
`therefore delta=r-30^@=45^@-30^@=15^@, therefore`DEVIATION of ray=`15^@`


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