A ray of light is incident on the surface of a glass plate of refracti

1.	A ray of light is incident on the surface of a glass plate of refractive index 1.55 at the polarising angle. Calculate the angle of refraction.
Answer» Given: R.I. of glass, μ = 1.55 To find: Angle of refraction (r) Formula: tan i_p = μ Calculation: From formula, tan i_p = 1.55 \(\therefore\) i_p = tan^-1(1.55) = 57°10' Since i_p + r = 90°, \(\therefore\) r = 90° – i_p = 90°– (57°10') \(\therefore\) r = 32°50' The angle of refraction of the ray of light is 32°50'.

A ray of light is incident on the surface of a glass plate of refractive index 1.55 at the polarising angle. Calculate the angle of refraction.

Answer»

Given: R.I. of glass, μ = 1.55

To find: Angle of refraction (r)

Formula: tan i_p = μ

Calculation: From formula,

tan i_p = 1.55

\(\therefore\) i_p = tan^-1(1.55) = 57°10'

Since i_p + r = 90°,

\(\therefore\) r = 90° – i_p = 90°– (57°10')

\(\therefore\) r = 32°50'

The angle of refraction of the ray of light is 32°50'.