A ray of light travels from an optically denser to rarer medium. The c

1.	A ray of light travels from an optically denser to rarer medium. The critical angle of the two media is ‘C’. What is the maximum possible deviation of the ray?
Answer» The relation between angle of deviation and angle of incidence, angle of emergence and angle of prism is given by Angle of deviation = i₁ + i₂ – A For maximum deviation, Angle of incidence (i₁) = 90° Angle of emergence (i₂) = 90° We know, μ = 1/ sin C . 1/ sin A/2 [Where C = Critical angle, A = Angle of prism] ∴ A = 2C ∴ Maximum deviation = i₁ + i₂ – A = 90 + 90 – 2C = 180 – 2C = n – 2C.

A ray of light travels from an optically denser to rarer medium. The critical angle of the two media is ‘C’. What is the maximum possible deviation of the ray?

Answer»

The relation between angle of deviation and angle of incidence, angle of emergence and angle of prism is given by

Angle of deviation = i₁ + i₂ – A

For maximum deviation, Angle of incidence (i₁) = 90°

Angle of emergence (i₂) = 90°

We know, μ = 1/ sin C . 1/ sin A/2 [Where C = Critical angle, A = Angle of prism]

∴ A = 2C

∴ Maximum deviation = i₁ + i₂ – A = 90 + 90 – 2C = 180 – 2C = n – 2C.