A ray of light undergoes deviation of 30^@ when incident on the equilateral prism of refractive index sqrt2. What is the angle subtended by the ray inside the prism with the base of the prism?

A ray of light undergoes deviation of 30^@ when incident on the equila

1.	A ray of light undergoes deviation of 30^@ when incident on the equilateral prism of refractive index sqrt2. What is the angle subtended by the ray inside the prism with the base of the prism?
Answer» Solution :Here `delta=30^@ and A=60^@` So if the prism had been in MINIMUM deviation, `mu= (sin[30^@+60^@]//2)/(sin (60^@//2))=sin 45^@/sin 30^@=1/sqrt2 times 2=sqrt2` And as `mu` of the prism is given to be `sqrt2` The prism is in the position implies that `r_1=r_2=r=(A/2)=(60^@/2)=30^@` Therefore, angle subtended by the ray INSIDE the prism with the surface `AB(90^@-r)=(90^@-30^@)=60^@` and as base also SUBTENDS an angle of `60^@` with the face AB, the ray inside the prism in parallel to the base i.e., the angle subtended by the ray inside the prism with the base is zero.