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A reaction A → B follows a second order kinetics Doubling the concentration of A will increase the rate of formation of B by a factor of : (a) 1/4 (b) 4 (c) 1/2 (d) 2 |
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Answer» Correct option (b) 4 Explanation: Rate = k[A]2 when concentration is doubled r = k[(2A)2 = k 4[A]2 The new rate become 4 times |
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