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InterviewSolution
| 1. |
A reaction A → B follows a second order kinetics Doubling the concentration of A will increase the rate of formation of B by a factor of : (a) 1/4 (b) 4 (c) 1/2 (d) 2 |
| Answer» <p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Correct option (b) 4 </strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000"><strong>Explanation:</strong></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">Rate = k[A]<sup>2</sup> when concentration is doubled</span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">r = k[(2A)<sup>2</sup></span></span></p><p style="text-align: justify;"><span style="font-family:Arial,Helvetica,sans-serif"><span style="color:#000000">= k 4[A]<sup>2 </sup>The new rate become 4 times</span></span></p> | |