A reaction `CaF_(2)hArrCa^(2+)+2F^(-)` is at equilibrium. If the concentration of `Ca^(2+)` is increased four times, what will be the change in `F^(-)` concentration as compared to the initial concentration of `F^(-)`?A. `1//4` of the initial valueB. `1//2` of the initial valueC. `2` times of the initial valueD. none of these

A reaction `CaF_(2)hArrCa^(2+)+2F^(-)` is at equilibrium. If the conce

1.	A reaction `CaF_(2)hArrCa^(2+)+2F^(-)` is at equilibrium. If the concentration of `Ca^(2+)` is increased four times, what will be the change in `F^(-)` concentration as compared to the initial concentration of `F^(-)`?A. `1//4` of the initial valueB. `1//2` of the initial valueC. `2` times of the initial valueD. none of these
Answer» `K_(c)=[Ca^(2+)][F^(-)]^(2)`, If `[Ca^(2+)]=4xx[Ca^(2+)]`, To have `K_(c)` constant `[F^(-)]` should be `([F^(-)])/(2)`.

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