1.

In an equilibrium `A+B hArr C+D`, A and B are mixed in vessel at temperature T. The initial concentration of A was twice the initial concentration of B. After the equilibrium has reaches, concentration of C was thrice the equilibrium concentration of B. Calculate `K_(c)`.

Answer» Correct Answer - A::C
`{:(A,+,B,hArr,C,+,D,),(2a,,a,,0,,0,"Initial conc"),((2a-x),,(a-x),,x,,x,"Conc at Eq"):}`
Given, initially `[A]=2[B]=2a`
Let concentration of B initially be a "mole"/litre
`:. K_(C)=(x.x)/((2-x)(a-x))` …(i)
Given at equilibrium, `[C]=3[B]`
`:. x=3(a-x)`
`x=(3a)/4` …(ii)
`:.` By equations (i) and (ii),
`K_(c)=((3a)/4xx(3a)/4)/((2a-(3a)/4)(a-(3a)/4))=1.8`


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