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In an equilibrium `A+B hArr C+D`, A and B are mixed in vessel at temperature T. The initial concentration of A was twice the initial concentration of B. After the equilibrium has reaches, concentration of C was thrice the equilibrium concentration of B. Calculate `K_(c)`. |
Answer» Correct Answer - A::C `{:(A,+,B,hArr,C,+,D,),(2a,,a,,0,,0,"Initial conc"),((2a-x),,(a-x),,x,,x,"Conc at Eq"):}` Given, initially `[A]=2[B]=2a` Let concentration of B initially be a "mole"/litre `:. K_(C)=(x.x)/((2-x)(a-x))` …(i) Given at equilibrium, `[C]=3[B]` `:. x=3(a-x)` `x=(3a)/4` …(ii) `:.` By equations (i) and (ii), `K_(c)=((3a)/4xx(3a)/4)/((2a-(3a)/4)(a-(3a)/4))=1.8` |
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